Continuous-Claude-v3 is a Claude Code development environment that preserves working context between sessions, coordinates specialized agents, and stores project knowledge through ledgers, handoffs, and analysis tools. It is for people using Claude Code on ongoing or complex software work. Its catalogue entries are the skills, agents, hooks, plugin, and setting that provide its workflows and orchestration.
Getting it into your agent
One page per mod, every tool's command on it. A separate URL per tool would split the same page into five that compete with each other.
npx skills add parcadei/Continuous-Claude-v3 --skill residuesgit clone --depth 1 https://github.com/parcadei/Continuous-Claude-v3Wrote this? Show the measurements
A badge with what this costs and how it scanned, read live from this page, so it follows the numbers instead of freezing them. Markdown for a README, HTML for a documentation site or a project page.
[](https://agentmods.dev/skills/parcadei/continuous-claude-v3/residues)<a href="https://agentmods.dev/skills/parcadei/continuous-claude-v3/residues"><img src="https://agentmods.dev/badge/skills/parcadei/continuous-claude-v3/residues/github.svg" alt="Measured on agentmods" height="20"></a>Or the 80×15 button, for a site that already has a row of RSS and ATOM ones. Only the verdict fits; the numbers stay here.
<a href="https://agentmods.dev/skills/parcadei/continuous-claude-v3/residues"><img src="https://agentmods.dev/badge/skills/parcadei/continuous-claude-v3/residues.svg" alt="Reviewed on agentmods" width="80" height="20"></a>- NVIDIA SkillSpector warn
SkillSpector: 1 finding, up to medium
These are SkillSpector’s own severities. On a checked sample its high-severity flags on skills were ~96% false positives — a documented command, a public API, a “never do X” rule — so we show them as a caution to read, not a verdict. Why →
- medium Agent Snooping · line 76 Skill enumerates or reads other installed skills. Access to other skills' SKILL.md files or the skills directory reveals prompt instructions, capabilities, and secrets that should be invisible to peer skills.Fix: Remove all code or instructions that list or read other skills' files or directories. Skills should operate independently; cross-skill access is a privilege escalation.
What it costs to keep this loaded
Counted locally with the o200k_base tokenizer, which is exact for GPT models; Claude uses its own tokenizer and its counts differ. Treat this as one consistent yardstick across the catalogue rather than a bill. Prices are per million input tokens.
| Model | Per session | Once invoked |
|---|---|---|
| Fable 5.1 | $0.00012 | $0.01116 |
| Opus 5 | $0.00006 | $0.00558 |
| Sonnet 5 | $0.00002 | $0.00223 |
| Haiku 4.5 | $0.00001 | $0.00112 |
Grade A, and why
residues scanned grade A with 0 findings against 26 rules in 11 categories — prompt injection, anti-refusal, data exfiltration, privilege escalation, supply chain, agent snooping, system-prompt leakage, SSRF and excessive agency — measured 8d ago.
A static scan of the body, not an audit. Every finding is printed with the line that produced it so you can judge whether it matters here. A mod is markdown that instructs an agent; that is exactly why what it instructs is worth reading.
Nothing flagged
None of the 26 patterns this scan looks for appear in this file: no shell pipes, no recursive deletes, no credential paths, no hidden text, no instruction-override or anti-refusal phrasing, no agent-config snooping. That is not a guarantee, it is the absence of the things that are checkable.
How it starts
The opening of the file, as written. The whole thing — 77 lines — stays where its author put it; the contents beside it link to each section on GitHub.
Residues
When to Use
Use this skill when working on residues problems in complex analysis.
Decision Tree
-
Computing Residues
- Simple pole at z0:
- Res(f, z0) = lim_{z->z0} (z - z0)f(z)
sympy_compute.py limit "(z - z0)*f(z)" --var z --at z0
- Pole of order n:
- Res(f, z0) = (1/(n-1)!) * lim d^{n-1}/dz^{n-1}[(z-z0)^n f(z)]
sympy_compute.py diff "((z-z0)**n)*f(z)" --var z --order n-1
- L'Hopital shortcut for f = g/h with simple pole:
- Res(f, z0) = g(z0)/h'(z0)
- Simple pole at z0:
-
Identify Pole Order
- Simple pole: (z - z0)f(z) has finite limit
- Order n: (z - z0)^n f(z) has finite limit, but (z - z0)^{n-1} f(z) doesn't
sympy_compute.py limit "(z - z0)**n * f(z)" --var z --at z0
-
Essential Singularities
- Neither pole nor removable (e.g., e^{1/z} at z=0)
- Compute residue via Laurent series
sympy_compute.py series "exp(1/z)" --var z --at 0
-
Apply Residue Theorem
- oint_C f(z)dz = 2pii * (sum of residues inside C)
- Count only poles INSIDE the contour
z3_solve.py prove "pole_inside_contour"
Tool Commands
Sympy_Residue
uv run python -m runtime.harness scripts/sympy_compute.py residue "1/((z-1)*(z-2))" --var z --at 1
Sympy_Limit
uv run python -m runtime.harness scripts/sympy_compute.py limit "(z - z0)*f(z)" --var z --at z0
Sympy_Laurent
uv run python -m runtime.harness scripts/sympy_compute.py series "exp(1/z)" --var z --at 0
Z3_Pole_Inside
uv run python -m runtime.harness scripts/z3_solve.py prove "abs(z0) < R"
Key Techniques
From indexed textbooks:
- [Complex analysis an introduction to... (Z-Library)] The fact that the calculus of residues yields complex rather than real integrals is no dis¬ (49) with g(z) — z, we obtain <»» i>(”)=25 / f^w) = 2vi / /'() /(z) - w z dz. If (49) is applied with g(z) = zm, equation (50) is replaced by 2iri I |z-zo| = /'() f(z) - w zm dz. The right-hand member represents an analytic function of w for \w — ir0| < 8.
- [Complex analysis an introduction to... (Z-Library)] What are the possible values of r dz J /l — z2 over a closed curve in the region? THE CALCULUS OF RESIDUES The results of the preceding section have shown that the determination of line integrals of analytic functions over closed curves can be reduced to the determination of periods. Under certain circumstances it turns out that the periods can be found without or with very little computation.
- [Complex analysis an introduction to... (Z-Library)] Hint: Sketch the image of the imaginary axis and apply the argument principle to a large half disk. Evaluation of Definite Integrals. The calculus of residues pro¬ vides a very efficient tool for the evaluation of definite integrals.
- [Complex analysis an introduction to... (Z-Library)] The particular function 1 /(z — ay) has a vanishing period. The constant Rj which produces this result is called the residue of f(z) at the point ay. We repeat the definition in the following form: It is helpful to use such self-explanatory notations as R = Res!
- [Complex Analysis (Elias M. Stein, Ram... (Z-Library)] Cauchy, 1826 There is a general principle in the theory, already implicit in Riemann’s work, which states that analytic functions are in an essential way charac- terized by their singularities. That is to say, globally analytic functions are “eectively” determined by their zeros, and meromorphic functions by their zeros and poles. While these assertions cannot be formulated as precise general theorems, there are nevertheless signicant instances where this principle applies.
What ships with it
1 file beside SKILL.md in the same directory: the scripts, references and assets a skill reads on demand. Not counted in the per-session cost; read them before you install if any of them is executable.
What this file has done since we first saw it
Hashed on every crawl. A supply-chain change to an agent config is a question of when, not whether, so the history is kept rather than the latest state alone.
- 8d ago First seen · 77 lines · 12 tokens per session scan A e78931be069f
residues is a skill published in the GitHub repository parcadei/Continuous-Claude-v3 (3,937 stars, last pushed 7mo ago), licensed MIT. It adds 12 tokens to every session and 1,116 once invoked, about $0.0001 per session on Opus 5. A static security scan graded it A with 0 findings. No closer match exists in the catalogue, so it is treated as the original; first seen 2026-09-03.
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